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5p^2-p=18
We move all terms to the left:
5p^2-p-(18)=0
We add all the numbers together, and all the variables
5p^2-1p-18=0
a = 5; b = -1; c = -18;
Δ = b2-4ac
Δ = -12-4·5·(-18)
Δ = 361
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{361}=19$$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-1)-19}{2*5}=\frac{-18}{10} =-1+4/5 $$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-1)+19}{2*5}=\frac{20}{10} =2 $
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